How Many Valence Electrons Does Aluminum Have?

aluminum periodic table

Aluminum is an element with the symbol “Al” and atomic number 13.

Aluminum does not occur naturally as a pure metal; Since it is very reactive, it always combines with other elements. Its most widely known compounds are oxides and hydroxides from bauxite, in its water-soluble forms complexed with sulfates and chloride. Due to the formation of a protective aluminum layer on the surface, it is not damaged in contact with air, this feature makes it very resistant to corrosion in air or water.

In this article you can find the answer for How many valence electrons does aluminum have? Aluminum or Al atom is the fourteenth element in periodic table. Al atom has 3 unpaired electrons. Al atom is paramagnetic. You can find the Lewis Structure for Al in this website.

How many protons does aluminum have?

Protons of aluminum can be found easily with the help of periodic table. If you possess a periodic table or if you can find it online, you can find the atomic number of any element you want. In this case, we need the atomic number of aluminum to find how many protons aluminum has. Because atomic number is equal to the number of protons for atoms. Atomic number of Al is 13. Therefore, Aluminum has 13 protons.

Here is the periodic table for you to find atomic number of aluminum:

Source: Brittanica

As you can see in the periodic table, Aluminum is placed at the 13th group under B atom and above Ga atom. The atomic number of Aluminum is 13.

How many protons neutrons and electrons does aluminum have

Aluminum has 13 protons. And if you want to find number of neutrons in Aluminum, you need to know the atomic mass of aluminum which is 27. Number of neutrons for Aluminum can be found by substracting proton number from atomic mass. So, neutron number is equal to 27-13 = 14. Aluminum has 14 neutrons. And number of electrons is equal to number of protons. Herewith, Aluminum has 13 protons, 14 neutrons and 13 electrons.

Aluminum Valence Electrons

Aluminum is an element which is placed in the group 13 of the periodic table. How to find Aluminum Valence Electrons? Aluminum valence electrons can be found by checking the electron configuration of Aluminum. We’re looking for how many electrons are present in the last shell of Aluminum.

Nucleus and valence electrons

If an atom wants to create a bond with another atom, the valence electrons of both atoms gain importance. Valence electrons helps us to understand the atoms. Aluminum is the 13th element in the periodic table. It means that Aluminum atom has 13 protons and 13 electrons.

There is an easy path to find valence electron which are located in the last orbital of Aluminum. The easy way is to write the Aluminum electron configuration. The electrons in the last shell is equal to aluminum (Al) valence electrons. Therefore, Aluminum valence electrons are three.

How many valence electrons are in aluminum

Aluminum has 13 protons in total and it has 13 electrons located in its orbitals. How to find how many valence electrons in aluminum? To find out how many valence electrons in aluminum, the first thing to do is writing the electron configuration of Al atom. Because Al valence electrons are present in the last shell of the electron configuration of aluminum. In conclusion, there are three valence electrons in aluminum.

Number of valence electrons in aluminum

There is an easy way to calculate number of valence electrons in aluminum but you need to follow 3 steps to calculate it. We need the recipe, right? So, if you are looking for the valence electrons in a aluminum atom, what you need is electron configuration of aluminum! It seems very easy, am i right?

Once you have the full electron configuration for Al atom, you can easily calculate the aluminum valence electrons. This part will be focused on the electron configuration of aluminum. It will be our first step. Then we will use this information to go through the second and third steps.

Below you can see an image which shows the summary of principal energy levels, sublevels and orbitals to write down the electron configuration. As you can see, a different number of electrons can be present in every sublevels.

Summary of Principal Energy Levels, Sublevels, and Orbitals. Principal Energy Level. Number of Sublevels. Type of Sublevel. n= s (1 orbital) n= s (1 orbital), 2p (3 orbitals) n= s (1 orbital), 3p (3 orbitals) 3d (5 orbitals) n= s (1 orbital), 4p (3 orbitals) 4d (5 orbitals) 4f (7 orbitals)

Now we can write the electron configuration easily since we know Bohr model and sub-orbits.

Calculating number of electrons in Aluminum (Al)

Let’s go! First step is calculating number of electrons of a aluminum atom. How can we know how many electrons are in aluminum? Just check the periodic table. Because if we know the atomic number, we can find the proton number. And we can find the proton number, we can find the electron number. Very easy to remember, what do you say? There is a periodic table above, in the part of how many protons does al have. Please check it.

Periodic table can give us what we need because the atomic number of every element is indicated in the periodic table. The number above the elements are atomic numbers. We need the atomic number of aluminum so we need to find where is aluminum in the periodic table. Aluminum is a group 13 element. You can find it under B atom and above Ga atom in the periodic table. The number above the Aluminum is 13. It means that, atomic number of Al atom is 13.

In conclusion, electron number is equal to atomic number for Al atom. As we can see in the periodic table, Aluminum atomic number is 13 which means that the total number of electrons for Aluminum atom is 13.

Write the electron configuration for Aluminum

First step is successful. Let’s go to the second step. We know the electron number of aluminum, now we need electron configuration for Al atom. Electron configuration has a very important role for every atom because it shows us the valence electrons. Electron configuration indicates how to distribute electrons to sublevels.

In the first step, we found that aluminum atom has thirteen electrons. According to the Bohr model, we can arrange 13 electrons to write the electron configuration. First shell of aluminum atom which is 1s should have two electrons. The second shell of aluminum atom which is 2s and 2p should have eight electrons. The third shell of aluminum atom which is 3s and 3p should have three electrons. Sublevel distribution of electrons of aluminum is respectively 2, 8, 3. By using sub-orbits, we can write the electron configuration for aluminum as 1s2 2s2 2p6 3s2 3p1.

Find the last shell and calculate valence electrons for aluminum atom

Here we are. The last step…

In the second step, we were able to write the electron configuration of aluminum thanks to the information we got in the first step. In the third step which is the last, we need to find which shell is the valence shell for aluminum atom. Because last shell of the electron configuration is valence shell and the electrons in a valence shell is equal to valence electrons for every atom. According to the electron configuration of aluminum, the last shell is 3s2 3p1 and it has three electrons. In conclusion, the valence electrons in aluminum are 6.

What is the valency of aluminum(Al)?

Valency is called to indicate the capability of forming bonds with other atoms. Valency number or with its other name valence is the number of unpaired electrons in the atom. How to find unpaired electrons of aluminum? Unpaired electrons of aluminum can be found in the last shell of atoms.

Electron configuration for Al atom is 1s2 2s2 2p6 3s2 3p1. According to the electron configuration of aluminum, there is 1 unpaired electron in the last orbit which is 3p1. In conclusion, the valency of Al atom is 1.

Lewis Structure for Aluminum can be found in ChemHelps.

Don’t forget to check out “How to Draw H2O Lewis Structure“, “How to Draw CO Lewis Structure” and “How Many Valence Electrons Does Calcium Have” articles to learn more about chemistry.

Another great source for chemistry “CH3CH2CH3 Lewis Structure“.

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