How Many Moles of NH3 Can Be Produced from 13.5 mol of H2 and Excess N2?

nh3-periodic-table

3 H2 (g) + N2 (g)→ 2 NH3(g)a

In this article you can find the answer for How Many Moles of NH3 Can Be Produced from 13.5 mol of H2 and Excess N2. Also you can find answers for:

  • How many grams of NH3 can be produced from 4.90 mol of N2 and excess H2
  • How many grams of H2 are needed to produce 12.74 g of NH3?
  • How many molecules (not moles) of NH3 are produced from 1.05×10^-4 g of H2?
nh3 periodic table, moles of nh3

How Many Moles of NH3 Can Be Produced from 13.5 mol of H2 and Excess N2?

For every 3 moles of H2, 2 of NH3 can be produced. If we multiply the amount of hydrogen by 2/3 and we can get the answer.

9 moles of NH3 are produced from 13.5 mol of H2 and excess N2.

How Many Moles of NH3 Can Be Produced from 13.5 mol of H2 and Excess N2?

How many grams of NHcan be produced from 4.90 mol of N2 and excess H2?

N2 + 3H2 = 2NH3 

1 mol of nitrogen + hydrogen produces 2(14+3) = 34 grams NH3

4.9 mol of N and H produces 34 * 4.9 grams NH3 

Answer is 166.6 grams of NH3 can be produced from 4.90 mol of N2 and excess H2.

How many grams of H2 are needed to produce 12.74 g of NH3?

M (NH3) = 14.01 + 1.008*3 = 17.034

m (NH3 = 12.74

n(NH3 = 12.74/17.034 = 0.749

For every two moles of NH3, you need 3 moles of H2.

0.749 * 3/2 moles of H2 = 1.12 mol

M(H2 = 2.016
m = n*M = 1.12 mol * 2.016 g/mol = 2.25

About 2.25 grams of H2

Answer is 2.25 grams of H2 are needed to produce 12.74 g of NH3.

How many molecules (not moles) of NH3 are produced from 1.05×10^-4 g of H2?

m(NH₃) = 1.05 × 10⁻⁴ g NH₃

M(NH₃) = 14.007 g/mol N + (3 × 1.008 g/mol H) = 17.031 g NH₃/mol NH₃

n(NH₃) = 1.05 × 10⁻⁴ g NH₃/17.031 g NH₃/mol NH₃ = 6.16 × 10^-6 mol NH₃

Calculate the number of molecules of NH₃ in 6.16 × 10^-6 mol.

1 mole of molecules = 6.022 × 10²³ molecules

6.16 × 10^-6 mol NH₃ × 6.022 × 10²³ NH₃ molecules/mol NH₃ = 37.09 × 10^17 NH₃

The number of molecules of NH3 are produced from 1.05 × 10^-4 g is 37.09 × 10^17.

We tried to answer the question “How Many Moles of NH3 Can Be Produced from 13.5 mol of H2 and Excess N2” in this article. And also we tried to find answers for “How many grams of NHcan be produced from 4.90 mol of N2 and excess H2?“, “How many grams of H2 are needed to produce 12.74 g of NH3” and “How many molecules (not moles) of NH3 are produced from 1.05×10^-4 g of H2” If you need any help with other chemistry related problems, contact us.

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