C4H10 Lewis Structure

Butane Lewis Structure

C4H10 is known as butane. ChemHelps will try to teach you how to draw C4H10 Lewis Structure in this article. There are 4 steps we need to check before drawing lewis structure of C4H10:

  1. First of all, we need to calculate the valence electrons of carbonate ion. C4H10 ion has 26 valence electrons.
  2. Then we need to find total electron pairs of C4H10.
  3. Center atom should be determined to draw butane lewis structure.
  4. And lastly, we need to find lone pairs and charges of C4H10 molecule.

Let’s start to find out C4H10 Lewis Structure, shall we?

How to Draw C4H10 Lewis Structure

Let’s find valence electrons of C4H10 first.

1 – Valence electrons in C4H10

C4H10 molecule has 4 Carbon atoms and 10 Hydrogen atoms. C is the symbol of Carbon and H is the symbol of Hydrogen atom. C has 4 valence electrons while H has 1 valence electron. Let’s multiply these with atoms, 4*4 + 1*10 = 26 valence electrons. So, valence electrons in C4H10 is 26.

What is the molecular shape of butane?

Butane’s molecular shape is tetrahedral. Carbon atoms in the butane are sp3 and have 109 degrees angle.

2 – Total electron pairs of C4H10

Divide total valence electrons by two to find the total electron pairs of C4H10. 26/2 = 13 electron pairs in C4H10.

3 – Center atom of C4H10

Carbon is the center atom of C4H10.

4 – Lone pairs and charges of C4H10

Formal charge of C4H10 is 0. To draw C4H10 Lewis, you should put all 4 carbon atoms in a row and put Hydrogen atoms around them.

Carbon should have 8 electrons which means that carbon should form 4 bonds. There are 10 oxygen atoms and 4 Carbon atoms. It means that it’s not very complicated to draw it.

Let’s find it out now:

C4H10 lewis structure
C4H10 Lewis Structure

Lewis Structure for C4H10

C4H10 is not a complex molecule. Since C4H10 has 24 valence electrons. And carbon should form 4 bonds. It makes this molecule a simple Lewis because all 4 carbons and 10 hydrogen atoms share a single bond. There is no formal charge and there is no lone pairs. It’s that easy to draw butane lewis dot structure.

Let’s find butane lewis structure now:

What we need first is to find valence electrons in butane to draw C4H10 Lewis Dot Structure.

C4H10 Valence Electrons

C4H10 has 4 C atom and 10 H atoms. Carbon has 4 valence electrons while H has 1 valence electron. All we need to do calculating total valence electrons.

4*4 + 1*10 = 26 valence electrons in C4H10.

Total electron pairs in C4H10:

If we divide total valence electrons in C4H10 by 2, the result would be total electron pairs in C4H10. So, if we divide 26 by 2, it would be 13. There are 13 electron pairs in C4H10.

Center atom:

Center atom of C4H10 is C atom.

Lone pairs and charges:

Formal charge of C4H10 is zero. All carbon atoms and hydrogen atoms share a single bond between them. Now we can draw C4H10 Lewis Dot Structure:

C4H10 lewis structure
Lewis Structure for C4H10

C4H10 Lewis Dot Structure

C4H10 Lewis Dot Structure is not a complex Lewis. It’s easy to draw even if you are not familiar with the topic. All you need to do is to check C2H5OH Lewis Structure first to get familiar with Lewis Structures before you try to draw Lewis Structure of butane.

Butane Lewis Structure

Butane is one of the easiest Lewis Structures. Let’s start with our 4-step Lewis drawing solution. It’s very easy when you know the necessary steps to draw butane lewis structure. First step is to calculate total valence electrons in butane. And then we calculate total electron pairs. After that, we find which atom is the center atom of our structure. Finally, we check the formal check and place lone pairs on atoms. And it’s that easy to draw a Lewis.

Calculating valence electrons in butane

How many valence electrons does butane has? Butane is formed by 4 carbon atom and 10 hydrogen atoms. And its formal charge is 0. So, in total butane has 26 valence electrons.

Carbon has 4 valence electrons * 4 atoms = 16 valence electrons from Carbon atom

Hydrogen has 1 valence electron * 10 atoms = 10 valence electrons from Hydrogen atoms

16 + 10 = 26 valence electrons

There are 26 valence electrons in butane. Or we can say that C4H10 has 26 valence electrons.

Calculating total electron pairs in butane

To find the total electron pairs in butane, all we need to do is to divide total valence electrons by 2. Which means that there are 13 electron pairs in butane. Because dividing 26 by 2 is equal to 13.

24/2 = 12 electron pairs in Butane.

C4H10 or Butane has 13 electron pairs in total.

Determining center atom of butane

Carbon is the center atom of butane lewis structure.

Calculating lone pairs and charges of butane

Formal charge of butane is 0.

Let’s draw lewis structure of butane to see lone pairs and charges.

C4H10 lewis structure
Butane Lewis Structure

CH3CH2CH2CH3 Lewis Structure

CH3CH2CH2CH3 Lewis Structure is also known as butane lewis structure. Because CH3CH2CH2CH3 is also the symbol of C4H10. To draw lewis structure for CH3CH2CH2CH3 you need to know how many valence electrons in CH3CH2CH2CH3.

What is the chemical name for the compound ch3ch2ch2ch3?

Chemical name for the compound CH3CH2CH2CH3 is Butane. It’s also shown as C4H10.

4 carbon atoms bring 16 valence electrons and 10 hydrogen atoms bring 10 valence electrons. In total ch3ch2ch2ch3 has 26 valence electrons. Dividing valence electrons by 2, you can find out total electron pairs in CH3CH2CH2CH3. It has 13 total electron pairs. Center atoms are carbon atoms. You need to put all 4 carbon atoms in a row and place hydrogen atoms around them while drawing CH3CH2CH2CH3 Lewis Structure.

Formal charge of CH3CH2CH2CH3 is zero. It has no lone pairs. So it’s very easy to draw lewis structure of CH3CH2CH2CH3 now:

CH3CH2CH2CH3 Lewis Structure

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