In Each Reaction Box Place the Best Reagent and Conditions from the List Below

In each reaction box, place the best reagent and conditions from the list below is a question that you can’t find an answer to. We know. Because websites like Chegg wants to charge you to show you these simple answers. But we don’t! You can find the free answer of in each reaction box, place the best reagent and conditions from the list below question here in ChemHelps.

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In each reaction box, place the best reagent and conditions from the list below

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How to Solve Reaction Box Questions

Step 1 : Analyse the reaction

You need to figure out if the reaction is aliphatic or aromatic and saturated or unsatured.

Step 2 : Count the number of carbons

Count the number of carbons on each side of the problem to find out if the number of carbons increased or decreased. It’s very important.

Step 3 : IUPAC Name of the compound

Find the IUPAC names of the compounds. It will help you to learn the behaviour of the compounds.

Step 4 : Choosing the best reagent conditions

Check the oxidizing and reducing agents / acidic and basic reagents.

Step 5 : Learn reaction types

You should learn the frequently used reactions in organic chemistry to solve this type of question. Halogenation, oxidation and reduction, nitration are some of the most frequently used reactions in organic chemistry.

Let’s solve a question together!

Answer of in each reaction box, place the best reagent and conditions from the list below

In each reaction box, place the best reagent and conditions from the list below.

Let’s start!

As you can see, on the left side, there are 2 carbon atoms with a triple bonding. It means that it’s an alkyne named acetylene or ethyne. On the right side, there are four carbon atoms and two Br atoms. The IUPAC name of the compound is 2,2-dibromo butane. If you count the carbon atoms, you can see that the number of carbon atoms is increased to 4. And the triple bond between carbon atoms changed to single bond.

Now, what we need is an acetylide ion. Because we want to form new carbon atoms and an acetylide ion can react with alkyl halides easily. It means that first, we need NaNH2. Then, as you know we need 2 more carbon atoms. How can we get the carbon atoms? If you check our options you will see that only CH3-CH2-Br has 2 carbon atoms that we need. It will provide us 1-butyne. But we need 2,2-dibromo butane.

We need to add 2 Br atoms to our compound and remove the triple bonding. We can use HBr 2-equiv to add 2 Br atoms to our compound. Br atoms remove triple bonding and we get single bonding between our atoms.

Here is the answer:

Now you can easily solve other problems.

Check out our Lewis structure calculator to solve your problems!