XeF2 is known as Xenon Difluoride. ChemHelps will try to teach you how to draw XeF2 Lewis Structure in this article. There are 4 steps we need to check before drawing lewis structure of XeF2:

- First of all, we need to calculate the valence electrons of Xenon Difluoride. XeF2 molecule has 22 valence electrons.
- Then we need to find total electron pairs of XeF2.
- Center atom should be determined to draw
**xenon difluoride lewis structure**. - And lastly, we need to find lone pairs and charges of XeF2 molecule.

Let’s start to find out **XeF2 Lewis Structure**, shall we?

### How to Draw XeF2 Lewis Structure

Let’s find valence electrons of XeF2 first.

**1 – Valence electrons in XeF2**

XeF2 molecule has 2 F atoms and 1 Xe atom. Xe is the symbol of Xenon and F is the symbol of fluorine. Xe has 8 valence electrons while F has 7 valence electrons. Let’s multiply these with atoms, 8*1 + 7*2 = 22 valence electrons. Valence electrons in XeF2 is 22.

**What is the hybridization for Xe in the XeF2 molecule?**

XeF2’s hybridization (Xenon Difluoride) is **sp3d** type.

**2 – Total electron pairs of XeF2**

Divide total valence electrons by two to find the total electron pairs of XeF2. 22/2 = **11 electron pairs** **in XeF2**.

**3 – Center atom of XeF2**

Between Xenon and fluorine, Xenon is the least electronegative atom. That’s why the center atom of XeF2 is Xenon. Because the least electronegative atom in the molecule is accepted as center atom.

**4 – Lone pairs and charges of XeF2**

Xenon can accept more than 8 valence electrons. So there is no lone pairs left alone. The charge of XeF2 is zero. Formal charge of XeF2 is zero. Here is **XeF2 Lewis Structure** according to these informations:

## Lewis Structure for XeF2

XeF2 is a complex molecule. Since XeF2 has 22 valence electrons, one of the atoms should accept more than 8 electrons or XeF2 should form double bond. But we know that Xe and F don’t form double bond. The key part of drawing XeF2 is knowing Xe can accept more than 8 electrons. Lewis Structure for XeF2 can be found by calculating valence electrons, total pair of electrons, lone pairs, charges and center atom. There are 4 steps we need to go off first before we draw **Lewis Structure for xenon difluoride**.

Let’s find **xenon difluoride** Lewis Structure now:

What we need first is to find **valence electrons in XeF2** to draw **XeF2 Lewis Dot Structure**.

XeF2 has 1 xenon atom and 2 fluorine atoms. Xe has 8 valence electrons while F has 7 valence electron only. And it’s that easy to calculate total valence electrons.

8*1 + 7*2 = 22 valence electrons in XeF2.

**Total electron pairs in XeF2:**

If we divide total valence electrons in XeF2 by 2, the result would be total electron pairs in XeF2. So, if we divide 22 by 2, it would be 11. There are 11 electron pairs in XeF2.

**Center atom:**

Center atom of XeF2 is Xe atom. Because Xenon’s electronegativity is lower than fluorine’s electronegativity.

**Lone pairs and charges:**

Formal charge of XeF2 is zero. Now we can draw XeF2 Lewis Dot Structure:

### Lewis Structure of XeF2

Lewis Structure of XeF2 is a complex Lewis. It’s not easy to draw if you are not familiar with the topic. You should be checking Acetic Acid Lewis Structure or CO2 Lewis Structure first to get familiar with Lewis Structures before you try to draw **Lewis Structure of xenon difluoride **.

**Calculating valence electrons in XeF2**

How many valence electrons does XeF2 has? XeF2 is formed by 1 xenon atom and 2 fluorine atoms. Thus, it has 22 valence electrons.

Xenon has 8 valence electrons * 1 atoms = **8 valence electrons from Xenon atom**

fluorine has 7 valence electron * 2 atoms = **14 valence electrons from fluorine atoms**

**In total 8 + 7 = 22 valence electrons**

**There are 22 valence electrons in xef2.** Or we can say that XeF2 has 22 valence electrons.

**Calculating total electron pairs in xef2**

To find the total electron pairs in xef2, all we need to do is to divide total valence electrons by 2. Which means that there are 11 electron pairs in xef2. Because dividing 22 by 2 is equal to 11.

22/2 = 11 electron pairs in xef2.

XeF2 or **xenon difluoride** has 11 electron pairs in total.

**Determining center atom of ****xenon difluoride**

**xenon difluoride**

Xenon is the center atom of **xenon difluoride** lewis structure.

### Calculating lone pairs and charges of xef2

Formal charge of **xenon difluoride** is 0.

Let’s draw lewis structure of **xenon difluoride** to see lone pairs and charges.

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