XeF2 is known as Xenon tetrafluoride. ChemHelps will try to teach you how to draw XeF4 Lewis Structure in this article. There are 4 steps we need to check before drawing Lewis structure of XeF4:

- First of all, we need to calculate the valence electrons of Xenon tetrafluoride. XeF4 molecule has 36 valence electrons.
- Then we need to find total electron pairs of XeF4.
- The center atom should be determined to draw
**Xenon tetrafluoride lewis structure**. - And lastly, we need to find lone pairs and charges of XeF4 molecule.

Let’s start to find out **XeF4 Lewis Structure**, shall we?

### How to Draw XeF4 Lewis Structure

Let’s find valence electrons of XeF4 first.

**1 – Valence electrons in XeF**4

XeF4 molecule has 4 F atoms and 1 Xe atom. Xe is the symbol of Xenon and F is the symbol of fluorine. Xe has 8 valence electrons while F has 7 valence electrons. Let’s multiply these with atoms, 8*1 + 7*4 = 36 valence electrons. Valence electrons in XeF4 is 36.

**What is the hybridization for Xe in the XeF4 molecule?**

XeF4’s hybridization (Xenon tetrafluoride) is **sp3d**2 type.

**2 – Total electron pairs of XeF4**

Divide total valence electrons by two to find the total electron pairs of XeF4. 36/2 = **18 electron pairs** **in XeF4**.

**3 – Center atom of XeF4**

Between Xenon and fluorine, Xenon is the least electronegative atom. That’s why the center atom of XeF4 is Xenon. Because the least electronegative atom in the molecule is accepted as the center atom.

**4 – Lone pairs and charges of XeF4**

There are 2 lone pairs in XeF4. The charge of XeF4 is zero. The formal charge of XeF4 is zero. Here is **XeF4 Lewis Structure** according to these information:

## Lewis Structure for XeF4

XeF4 is a complex molecule. Since XeF4 has 36 valence electrons, you should be very careful while drawing the structure. Lewis Structure for XeF4 can be found by calculating valence electrons, total pair of electrons, lone pairs, charges and center atom. There are 4 steps we need to go off first before we draw **Lewis Structure for xenon tetrafluoride**.

Let’s find **xenon tetrafluoride** Lewis Structure now:

What we need first is to find **valence electrons in XeF4** to draw **XeF4 Lewis Dot Structure**.

XeF4 has 1 xenon atom and 4 fluorine atoms. Xe has 8 valence electrons while F has 7 valence electrons only. And it’s that easy to calculate total valence electrons.

8*1 + 7*4 = 36 valence electrons in XeF4.

**Total electron pairs in XeF4:**

If we divide total valence electrons in XeF4 by 2, the result would be total electron pairs in XeF4. So, if we divide 36 by 2, it would be 18. There are 18 electron pairs in XeF4.

**Center atom:**

The Center atom of XeF4 is the Xe atom. Because Xenon’s electronegativity is lower than fluorine’s electronegativity.

**Lone pairs and charges:**

Formal charge of XeF4 is zero. Now we can draw XeF4 Lewis Dot Structure:

### Lewis Structure of XeF4

Lewis Structure of XeF4 is a complex Lewis. It’s not easy to draw if you are not familiar with the topic. You should be checking Acetic Acid Lewis Structure or CO2 Lewis Structure first to get familiar with Lewis Structures before you try to draw **Lewis Structure of xenon tetrafluoride **.

**Calculating valence electrons in XeF4**

How many valence electrons does XeF4 has? XeF4 is formed by 1 xenon atom and 4 fluorine atoms. Thus, it has 36 valence electrons.

Xenon has 8 valence electrons * 1 atoms = **8 valence electrons from Xenon atom**

fluorine has 7 valence electron * 4 atoms = **28 valence electrons from fluorine atoms**

**In total 8 + 28 = 36 valence electrons**

**There are 36 valence electrons in xef4.** Or we can say that XeF4 has 36 valence electrons.

**Calculating total electron pairs in xef4**

To find the total electron pairs in xef4, all we need to do is to divide total valence electrons by 2. Which means that there are 18 electron pairs in xef2. Because dividing 36 by 2 is equal to 18.

36/2 = 18 electron pairs in xef4.

XeF4 or **xenon tetrafluoride** has 18 electron pairs in total.

**Determining center atom of ****xenon tetrafluoride**

**xenon tetrafluoride**

Xenon is the center atom of **xenon tetrafluoride** lewis structure.

### Calculating lone pairs and charges of xef2

Formal charge of **xenon tetrafluoride** is 0.

Let’s draw lewis structure of **xenon tetrafluoride** to see lone pairs and charges.

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